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Result
... Pound-force foot per pound degree Rankine = ... Joule per kilogram degree Celsius
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Pound-force foot per pound degree Rankine to Joule per kilogram degree Celsius Converter
Use this page to convert pound-force foot per pound degree rankine values into joule per kilogram degree celsius, with background details, formulas, a worked example, and a quick conversion table.
Conversion formula
1 lbf*ft/(lb*deg R) = 5.380320456 J/(kg*deg C)
1 J/(kg*deg C) = 0.185862535173871 lbf*ft/(lb*deg R)
Example: 4186 lbf*ft/(lb*deg R) = 22,522.021428816 J/(kg*deg C)
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Pound-force foot per pound degree Rankine
One pound-force foot per pound degree Rankine is equal to 5.380320456 joules per kilogram kelvin.
History: This unit links customary mechanical work with temperature intervals on the Rankine scale.
Current use: It is useful for older US engineering calculations and source-table compatibility.
Also written as lbf*ft/(lb*deg R).
Joule per kilogram degree Celsius
One joule per kilogram degree Celsius is equal to one joule per kilogram kelvin.
History: Celsius interval units are often used alongside kelvin intervals in practical heat calculations.
Current use: This unit appears in material datasheets and engineering examples that use Celsius temperature changes.
Also written as J/(kg*deg C).
Pound-force foot per pound degree Rankine to Joule per kilogram degree Celsius table
| Pound-force foot per pound degree Rankine [lbf*ft/(lb*deg R)] | Joule per kilogram degree Celsius [J/(kg*deg C)] |
|---|---|
| 0.01 lbf*ft/(lb*deg R) | 0.05380320456 J/(kg*deg C) |
| 0.1 lbf*ft/(lb*deg R) | 0.5380320456 J/(kg*deg C) |
| 1 lbf*ft/(lb*deg R) | 5.380320456 J/(kg*deg C) |
| 2 lbf*ft/(lb*deg R) | 10.760640912 J/(kg*deg C) |
| 5 lbf*ft/(lb*deg R) | 26.90160228 J/(kg*deg C) |
| 10 lbf*ft/(lb*deg R) | 53.80320456 J/(kg*deg C) |
| 20 lbf*ft/(lb*deg R) | 107.60640912 J/(kg*deg C) |
| 50 lbf*ft/(lb*deg R) | 269.0160228 J/(kg*deg C) |
| 100 lbf*ft/(lb*deg R) | 538.0320456 J/(kg*deg C) |
