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... Pound-force foot per pound degree Rankine = ... Joule per gram degree Celsius

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Pound-force foot per pound degree Rankine to Joule per gram degree Celsius Converter

Use this page to convert pound-force foot per pound degree rankine values into joule per gram degree celsius, with background details, formulas, a worked example, and a quick conversion table.

Pound-force foot per pound degree Rankine

One pound-force foot per pound degree Rankine is equal to 5.380320456 joules per kilogram kelvin.

History: This unit links customary mechanical work with temperature intervals on the Rankine scale.

Current use: It is useful for older US engineering calculations and source-table compatibility.

Also written as lbf*ft/(lb*deg R).

Joule per gram degree Celsius

One joule per gram degree Celsius is equal to 1000 joules per kilogram kelvin.

History: Gram-based heat capacity units are convenient in chemistry and laboratory work.

Current use: This unit is common in chemistry, food science, and small-sample heat calculations.

Also written as J/(g*deg C).

Pound-force foot per pound degree Rankine to Joule per gram degree Celsius table

Pound-force foot per pound degree Rankine [lbf*ft/(lb*deg R)]Joule per gram degree Celsius [J/(g*deg C)]
0.01 lbf*ft/(lb*deg R)0.00005380320456 J/(g*deg C)
0.1 lbf*ft/(lb*deg R)0.0005380320456 J/(g*deg C)
1 lbf*ft/(lb*deg R)0.005380320456 J/(g*deg C)
2 lbf*ft/(lb*deg R)0.010760640912 J/(g*deg C)
5 lbf*ft/(lb*deg R)0.02690160228 J/(g*deg C)
10 lbf*ft/(lb*deg R)0.05380320456 J/(g*deg C)
20 lbf*ft/(lb*deg R)0.10760640912 J/(g*deg C)
50 lbf*ft/(lb*deg R)0.2690160228 J/(g*deg C)
100 lbf*ft/(lb*deg R)0.5380320456 J/(g*deg C)