Converter group
Heat Converters
Specific Heat Capacity Converter
Result
... Pound-force foot per pound degree Rankine = ... Joule per gram degree Celsius
Find the units to convert
Pound-force foot per pound degree Rankine to Joule per gram degree Celsius Converter
Use this page to convert pound-force foot per pound degree rankine values into joule per gram degree celsius, with background details, formulas, a worked example, and a quick conversion table.
Conversion formula
1 lbf*ft/(lb*deg R) = 0.005380320456 J/(g*deg C)
1 J/(g*deg C) = 185.862535173871 lbf*ft/(lb*deg R)
Example: 4186 lbf*ft/(lb*deg R) = 22.522021428816 J/(g*deg C)
Jump to another pair
Pound-force foot per pound degree Rankine
One pound-force foot per pound degree Rankine is equal to 5.380320456 joules per kilogram kelvin.
History: This unit links customary mechanical work with temperature intervals on the Rankine scale.
Current use: It is useful for older US engineering calculations and source-table compatibility.
Also written as lbf*ft/(lb*deg R).
Joule per gram degree Celsius
One joule per gram degree Celsius is equal to 1000 joules per kilogram kelvin.
History: Gram-based heat capacity units are convenient in chemistry and laboratory work.
Current use: This unit is common in chemistry, food science, and small-sample heat calculations.
Also written as J/(g*deg C).
Pound-force foot per pound degree Rankine to Joule per gram degree Celsius table
| Pound-force foot per pound degree Rankine [lbf*ft/(lb*deg R)] | Joule per gram degree Celsius [J/(g*deg C)] |
|---|---|
| 0.01 lbf*ft/(lb*deg R) | 0.00005380320456 J/(g*deg C) |
| 0.1 lbf*ft/(lb*deg R) | 0.0005380320456 J/(g*deg C) |
| 1 lbf*ft/(lb*deg R) | 0.005380320456 J/(g*deg C) |
| 2 lbf*ft/(lb*deg R) | 0.010760640912 J/(g*deg C) |
| 5 lbf*ft/(lb*deg R) | 0.02690160228 J/(g*deg C) |
| 10 lbf*ft/(lb*deg R) | 0.05380320456 J/(g*deg C) |
| 20 lbf*ft/(lb*deg R) | 0.10760640912 J/(g*deg C) |
| 50 lbf*ft/(lb*deg R) | 0.2690160228 J/(g*deg C) |
| 100 lbf*ft/(lb*deg R) | 0.5380320456 J/(g*deg C) |
