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Result
... Btu (IT) per pound degree Rankine = ... Joule per kilogram kelvin
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Btu (IT) per pound degree Rankine to Joule per kilogram kelvin Converter
Use this page to convert btu (it) per pound degree rankine values into joule per kilogram kelvin, with background details, formulas, a worked example, and a quick conversion table.
Conversion formula
1 Btu (IT)/(lb*deg R) = 4,186.8 J/(kg*K)
1 J/(kg*K) = 0.000238845896627496 Btu (IT)/(lb*deg R)
Example: 4186 Btu (IT)/(lb*deg R) = 17,525,944.8 J/(kg*K)
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Btu (IT) per pound degree Rankine
One Btu (IT) per pound degree Rankine is equal to 4,186.8 joules per kilogram kelvin.
History: Rankine interval units are common in US thermodynamics and absolute-temperature calculations.
Current use: This unit is used in thermodynamics references that prefer Rankine temperature intervals.
Also written as Btu (IT)/(lb*deg R).
Joule per kilogram kelvin
Joule per kilogram kelvin measures energy required per kilogram for a one-kelvin temperature change.
History: This SI unit is the standard reference for comparing material heat capacity.
Current use: It is used in thermodynamics, materials engineering, heating calculations, and simulation models.
Also written as J/(kg*K).
Btu (IT) per pound degree Rankine to Joule per kilogram kelvin table
| Btu (IT) per pound degree Rankine [Btu (IT)/(lb*deg R)] | Joule per kilogram kelvin [J/(kg*K)] |
|---|---|
| 0.01 Btu (IT)/(lb*deg R) | 41.868 J/(kg*K) |
| 0.1 Btu (IT)/(lb*deg R) | 418.68 J/(kg*K) |
| 1 Btu (IT)/(lb*deg R) | 4,186.8 J/(kg*K) |
| 2 Btu (IT)/(lb*deg R) | 8,373.6 J/(kg*K) |
| 5 Btu (IT)/(lb*deg R) | 20,934 J/(kg*K) |
| 10 Btu (IT)/(lb*deg R) | 41,868 J/(kg*K) |
| 20 Btu (IT)/(lb*deg R) | 83,736 J/(kg*K) |
| 50 Btu (IT)/(lb*deg R) | 209,340 J/(kg*K) |
| 100 Btu (IT)/(lb*deg R) | 418,680 J/(kg*K) |
