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Result
... Btu (IT) per pound degree Rankine = ... Joule per kilogram degree Celsius
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Btu (IT) per pound degree Rankine to Joule per kilogram degree Celsius Converter
Use this page to convert btu (it) per pound degree rankine values into joule per kilogram degree celsius, with background details, formulas, a worked example, and a quick conversion table.
Conversion formula
1 Btu (IT)/(lb*deg R) = 4,186.8 J/(kg*deg C)
1 J/(kg*deg C) = 0.000238845896627496 Btu (IT)/(lb*deg R)
Example: 4186 Btu (IT)/(lb*deg R) = 17,525,944.8 J/(kg*deg C)
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Btu (IT) per pound degree Rankine
One Btu (IT) per pound degree Rankine is equal to 4,186.8 joules per kilogram kelvin.
History: Rankine interval units are common in US thermodynamics and absolute-temperature calculations.
Current use: This unit is used in thermodynamics references that prefer Rankine temperature intervals.
Also written as Btu (IT)/(lb*deg R).
Joule per kilogram degree Celsius
One joule per kilogram degree Celsius is equal to one joule per kilogram kelvin.
History: Celsius interval units are often used alongside kelvin intervals in practical heat calculations.
Current use: This unit appears in material datasheets and engineering examples that use Celsius temperature changes.
Also written as J/(kg*deg C).
Btu (IT) per pound degree Rankine to Joule per kilogram degree Celsius table
| Btu (IT) per pound degree Rankine [Btu (IT)/(lb*deg R)] | Joule per kilogram degree Celsius [J/(kg*deg C)] |
|---|---|
| 0.01 Btu (IT)/(lb*deg R) | 41.868 J/(kg*deg C) |
| 0.1 Btu (IT)/(lb*deg R) | 418.68 J/(kg*deg C) |
| 1 Btu (IT)/(lb*deg R) | 4,186.8 J/(kg*deg C) |
| 2 Btu (IT)/(lb*deg R) | 8,373.6 J/(kg*deg C) |
| 5 Btu (IT)/(lb*deg R) | 20,934 J/(kg*deg C) |
| 10 Btu (IT)/(lb*deg R) | 41,868 J/(kg*deg C) |
| 20 Btu (IT)/(lb*deg R) | 83,736 J/(kg*deg C) |
| 50 Btu (IT)/(lb*deg R) | 209,340 J/(kg*deg C) |
| 100 Btu (IT)/(lb*deg R) | 418,680 J/(kg*deg C) |
