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Specific Heat Capacity Converter
Result
... Btu (IT) per pound degree Fahrenheit = ... Joule per kilogram kelvin
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Btu (IT) per pound degree Fahrenheit to Joule per kilogram kelvin Converter
Use this page to convert btu (it) per pound degree fahrenheit values into joule per kilogram kelvin, with background details, formulas, a worked example, and a quick conversion table.
Conversion formula
1 Btu (IT)/(lb*deg F) = 4,186.8 J/(kg*K)
1 J/(kg*K) = 0.000238845896627496 Btu (IT)/(lb*deg F)
Example: 4186 Btu (IT)/(lb*deg F) = 17,525,944.8 J/(kg*K)
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Btu (IT) per pound degree Fahrenheit
One Btu (IT) per pound degree Fahrenheit is equal to 4,186.8 joules per kilogram kelvin.
History: Btu per pound per Fahrenheit degree is a long-standing customary heat-capacity expression.
Current use: It is used in HVAC, combustion, building systems, and US engineering references.
Also written as Btu (IT)/(lb*deg F).
Joule per kilogram kelvin
Joule per kilogram kelvin measures energy required per kilogram for a one-kelvin temperature change.
History: This SI unit is the standard reference for comparing material heat capacity.
Current use: It is used in thermodynamics, materials engineering, heating calculations, and simulation models.
Also written as J/(kg*K).
Btu (IT) per pound degree Fahrenheit to Joule per kilogram kelvin table
| Btu (IT) per pound degree Fahrenheit [Btu (IT)/(lb*deg F)] | Joule per kilogram kelvin [J/(kg*K)] |
|---|---|
| 0.01 Btu (IT)/(lb*deg F) | 41.868 J/(kg*K) |
| 0.1 Btu (IT)/(lb*deg F) | 418.68 J/(kg*K) |
| 1 Btu (IT)/(lb*deg F) | 4,186.8 J/(kg*K) |
| 2 Btu (IT)/(lb*deg F) | 8,373.6 J/(kg*K) |
| 5 Btu (IT)/(lb*deg F) | 20,934 J/(kg*K) |
| 10 Btu (IT)/(lb*deg F) | 41,868 J/(kg*K) |
| 20 Btu (IT)/(lb*deg F) | 83,736 J/(kg*K) |
| 50 Btu (IT)/(lb*deg F) | 209,340 J/(kg*K) |
| 100 Btu (IT)/(lb*deg F) | 418,680 J/(kg*K) |
