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Specific Heat Capacity Converter
Result
... Btu (IT) per pound degree Fahrenheit = ... Joule per kilogram degree Celsius
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Btu (IT) per pound degree Fahrenheit to Joule per kilogram degree Celsius Converter
Use this page to convert btu (it) per pound degree fahrenheit values into joule per kilogram degree celsius, with background details, formulas, a worked example, and a quick conversion table.
Conversion formula
1 Btu (IT)/(lb*deg F) = 4,186.8 J/(kg*deg C)
1 J/(kg*deg C) = 0.000238845896627496 Btu (IT)/(lb*deg F)
Example: 4186 Btu (IT)/(lb*deg F) = 17,525,944.8 J/(kg*deg C)
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Btu (IT) per pound degree Fahrenheit
One Btu (IT) per pound degree Fahrenheit is equal to 4,186.8 joules per kilogram kelvin.
History: Btu per pound per Fahrenheit degree is a long-standing customary heat-capacity expression.
Current use: It is used in HVAC, combustion, building systems, and US engineering references.
Also written as Btu (IT)/(lb*deg F).
Joule per kilogram degree Celsius
One joule per kilogram degree Celsius is equal to one joule per kilogram kelvin.
History: Celsius interval units are often used alongside kelvin intervals in practical heat calculations.
Current use: This unit appears in material datasheets and engineering examples that use Celsius temperature changes.
Also written as J/(kg*deg C).
Btu (IT) per pound degree Fahrenheit to Joule per kilogram degree Celsius table
| Btu (IT) per pound degree Fahrenheit [Btu (IT)/(lb*deg F)] | Joule per kilogram degree Celsius [J/(kg*deg C)] |
|---|---|
| 0.01 Btu (IT)/(lb*deg F) | 41.868 J/(kg*deg C) |
| 0.1 Btu (IT)/(lb*deg F) | 418.68 J/(kg*deg C) |
| 1 Btu (IT)/(lb*deg F) | 4,186.8 J/(kg*deg C) |
| 2 Btu (IT)/(lb*deg F) | 8,373.6 J/(kg*deg C) |
| 5 Btu (IT)/(lb*deg F) | 20,934 J/(kg*deg C) |
| 10 Btu (IT)/(lb*deg F) | 41,868 J/(kg*deg C) |
| 20 Btu (IT)/(lb*deg F) | 83,736 J/(kg*deg C) |
| 50 Btu (IT)/(lb*deg F) | 209,340 J/(kg*deg C) |
| 100 Btu (IT)/(lb*deg F) | 418,680 J/(kg*deg C) |
