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... Btu (IT) per pound degree Fahrenheit = ... Joule per gram degree Celsius

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Btu (IT) per pound degree Fahrenheit to Joule per gram degree Celsius Converter

Use this page to convert btu (it) per pound degree fahrenheit values into joule per gram degree celsius, with background details, formulas, a worked example, and a quick conversion table.

Btu (IT) per pound degree Fahrenheit

One Btu (IT) per pound degree Fahrenheit is equal to 4,186.8 joules per kilogram kelvin.

History: Btu per pound per Fahrenheit degree is a long-standing customary heat-capacity expression.

Current use: It is used in HVAC, combustion, building systems, and US engineering references.

Also written as Btu (IT)/(lb*deg F).

Joule per gram degree Celsius

One joule per gram degree Celsius is equal to 1000 joules per kilogram kelvin.

History: Gram-based heat capacity units are convenient in chemistry and laboratory work.

Current use: This unit is common in chemistry, food science, and small-sample heat calculations.

Also written as J/(g*deg C).

Btu (IT) per pound degree Fahrenheit to Joule per gram degree Celsius table

Btu (IT) per pound degree Fahrenheit [Btu (IT)/(lb*deg F)]Joule per gram degree Celsius [J/(g*deg C)]
0.01 Btu (IT)/(lb*deg F)0.041868 J/(g*deg C)
0.1 Btu (IT)/(lb*deg F)0.41868 J/(g*deg C)
1 Btu (IT)/(lb*deg F)4.1868 J/(g*deg C)
2 Btu (IT)/(lb*deg F)8.3736 J/(g*deg C)
5 Btu (IT)/(lb*deg F)20.934 J/(g*deg C)
10 Btu (IT)/(lb*deg F)41.868 J/(g*deg C)
20 Btu (IT)/(lb*deg F)83.736 J/(g*deg C)
50 Btu (IT)/(lb*deg F)209.34 J/(g*deg C)
100 Btu (IT)/(lb*deg F)418.68 J/(g*deg C)